Saturday, 21 May 2016

D.C Supply (9v & 12v)


D.C Supply (9v & 12v)


In this kit we are using a.c. supply 230v single phase to convert it into d.c. supply by the circuit which is given below.



In this circuit we are using transformer to step down the a.c. supply which is centre tapped and a full bridge rectifier is connected which is conveting it into d.c. supply.
The positive cycle will be fed to the positive half cycle i.e. ic 7812 and the negative half cycle will be fed to the negative half cycle i.e. 7912. Thus, output is obtained.

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Voltage Regulator

Voltage Regulator



Voltage is regulated by this circuit . A.c single phase 230v supply is used. A step down transformer 230/18v is used which is converting 230v supply into 18v. A full wave bridge rectifier is using to convert that step down a.c. supply  into d.c supply. 
The positive half cycle is going to the positive terminal and and negative half cycle is goint to the negative terminal.
In positive terminal there is a ic 7812 which gives the positive output voltage and in negative terminal there is ic 7912 which gives negative output voltage.
On the positive terminal  there is another ic LM317 which two out of three terminals i.e. output and adjust are shprt circuited which gives the regulated output voltage and its input terminal is connected to the output terminal of ic7812.
Hence regulated output voltage is obtained at the positive terminal of the circuit. 

SuperPosition Theorem


Superposition Theorem

PROCEDURE:-

1- Superposition Theorem:- In a linear lumped bi-lateral network with more than one source of emf, the current flowing through any branch, when both the sources are active is equal to algebraic sum of current that would flow, if one source of emf is kept active and all other sources are dead.
2- The circuit connection are made as shown in diagram 1.
3- The current flowing through load resistor (R2) is noted (I) that is 10.14 mA.


4- The circuit connection are made as shown in circuit diagram 2, and the current through load resistor (R2) is noted (I1) that is 4.30 mA.
5- The circuit connection are made  as shown in circuit diagram 3, and the current flowing through load resistor (R2) is noted (I2) that is 5.76 mA.
6- It is observed I = I1 + I2

Calculation
  The value of current (I) = 10.01 mA
  The value of current (I1) = 4.30 mA
  The value of current (I2) = 5.76 mA
   
I = I1 + I2 = 4.30 + 5.76
                                                     = 10.06 mA ≈ I



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SCR Characteristics

SCR Characteristics

 Circuit used to plot characteristics of SCR is shown in diagram.

Procedure:- 

Make circuit connections as shown in the diagram 1 using patch cords.
1- To plot the V-I characteristics proceed as follows.
2- Rotate both the potentiometer P1 and P2 in fully counter clockwise direction, 3- connect voltmeter to point ‘6’ & ground to read VG and at point ‘3’ & ground to read VAK.
Connect ammeter at point ‘1’ & ‘2’ to indicate the current IA and at point ‘4’ & ‘5’ to indicate the gate current IG.
4- Switch on the power supply.
5- Vary potentiometer P2 to set the gate current IG to a lower value (5.6 mA, 5.7 mA, 5.8 mA).
6- Increase anode voltage VA gradually by varying potentiometer P1.
7- Observe the current IA in the anode circuit. It shows almost zero current  at the initial stage.
8- At certain point of positive anode voltage current IA shows sudden rise in reading & voltmeter reading falls down to almost zero. This action indicates the firing of SCR.
9- If this not happens, repeat the procedure from step 5 for slightly higher value of gate current IG.
10- Try the various value of gate current to get the firing of SCR.
11- Keeping gate current constant observe precisely the firing voltage of SCR and record it in the observation table.
12- Also record the anode voltage VA & anode current after firing of the SCR.
13- Plot the graph of VA versus IA.

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Ohm's Law


Ohm's Law


Ohm’s Law states that at constant temperature the current through a conductor is directly proportional to the potential difference across its ends.
If V is the potential difference and I is the current, then
I Proportional V
V/I = Constant
The constant is the resistance R of the conductor.


Procedure:-


1- Make connections as shown in circuit diagram.
2- Take least count of ammeter and voltmeter.
3- Plug the key. Note the readings of voltmeter and ammeter.
4- Repeat the experiment by adjusting the rheostat.
5- Draw a graph between V and I.

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Verification of Kirchhoff Law

Verification of Kirchhoff Law



Kirchoff’s Current  law:- 


(i)This law states that algebraic sum of all current entering a node and leaving a node is equal to zero.
(ii) The circuit connections are made as shown in circuit diagram.
(iii) At node “B” the incoming current is measured.
(iv) The outgoing current I2 and I3 are also measured.
(v) It is found that the sum of all the incoming and outgoing current is zero;
       I1=I2+I3

Kirchoff’s voltage law:- 


It states that algebraic sum of voltage rise is equal to algebraic sum of voltage rise is equal to algebraic sum of voltage drop in a closed path (circuit).
(ii) The circuit connection are made as shown in circuit diagram
(iii) The voltage across R1 and R2 and R 3 are measured.
(iv) V= VR1+VR2+VR3

AUTOMATIC LIGHTNING


AUTOMATIC LIGHTNING

It is a circuit which works as an automatic switch. It gets “On” & “OFF” automatically according to our desire. It works on the fact that its resistance decreases with increase in incident light i.e. daytime. And its resistance increases with the decrease in incident light i.e. night time.

 CIRCUIT DIAGRAM OF LDR


At day time
I1= 230/ (30×103+100)
I1= 7.395 mA
Voltage across 30kΩ
V (30kΩ) = 30×103×7.395×10-3
V= 221.85V
VL=230-221.85V
VL= 8.15V
The Voltage across the capacitor is 8.15V. The capacitor cannot discharge.
(i) There won’t be any pulse to the triac.
(ii)The triac will be in open circuit state no current will flow through the load .The light is ‘OFF’.
At night
I2= 230/(30×103+1×103+100×103)
I2= 1.75mA
Voltage across 30KΩ
Substitute the value of eqn.(ii) in above eqn.
We get 
V (30KΩ) = I2R
V (30KΩ) =30×103×1.75×10-5
V (30K Ω) = 52.5V
+VC=230-52.5
VC= 177.5V
The voltage across the capacitor is 177.5v .The capacitor will charge and discharge .
(i) There will be pulse through diac and hence gate pulse to the triac.
(ii) The triac will be in short circuit the lead. The light is “ON”.

Time constant in charging


Time constant in charging 

The time constant is the time taken by the capacitor(uncharged) to acquire 63% of the voltage being applied to it if it starts with zero volt. Equivalently, it is the time taken by a capacitor to acquire 63% of the difference between its initial voltage and voltage being supplied to it.
Calculating the time constant
Time Constant, t=RXC
R=330Ω and C=100µF
t=330ΩX100µF
=330ΩX100X10-6
=.0033second
Deriving the time constant from charging Curve
If we assume that the capacitor charges at a constant rate, it will add one volt in one second. In practice, this cannot happen. A capacitor adds up more volts in one second. To verify this, we will use experimental observation and plot the graph of voltage across the capacitor versus time .
Vcc=9V, R=1KΩ and C=1000µF
Let us first calculate the value of rc.
RC=1KX1000µF
     =1 second
Putting the value of RC and t in equation (A) we get
V=9(1-e-1/1)
    =9(1-e-1)
   =9(1-1/e)
    =9(1-1/2.71)
    =9(1-0.36)
    =9(0.63)
     =63%(9)
Thus the voltage gained by the capacitor in 1 second is equal to 63% of Vcc.



Circuit  Explaination


Charge the 100µF capacitor
Insert the wires attached to the meter probes in parallel with the series combination of LED and R. To do this, the red and black wires of the meter are connected to the left leg of R and the negative terminal of the LED.
Connect  the charged capacitor in parallel with the series combination of the LED and the resistor in such a way that its positive terminal is connected to the end of the resistor to which the red probe is connected and its negative terminal is connected to the negative terminal of the LED.

Observation:-


1) The meter will show a continuously decreasing voltage reading. The reading becomes steady after sometime.

2) The LED glows and then slowly fades out.

3) The rate of decrease of voltage reading is initially fast but subsequently slows down with time.

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DIAC Characteristics


DIAC  Characteristics


1- Make circuit as shown in the fig. using patch cords.
2- To plot V-I characteristics proceed as follows.
3- Rotate both the potentiometer P1 fully counter clockwise direction.
4- Connect voltmeter across point ‘3’ & ground to read voltage VA.
5- Connect ammeter between point ‘1’n& ‘2’ to indicate the current IA.
6- Switch ‘ON’ the power supply.
7- Put the +35 v switch ‘ON’.
8- Vary the potentiometer P1 so as to increase the value of DIAC voltage VA and measure the corresponding values of current IA in an observation table1.
9- Plot the curve between +VA and +IA
10- Rotate potentiometer P1 fully in counter clockwise direction.
11- Switch ‘OFF’ the power supply.
12- Put the switch towards -35V
13-Switch ‘ON’ the power supply.
14- Vary the potentiometer P1 so as to increase the value of DIAC voltage VA and measure the  corresponding values of current IA in an observation table.
15- Plot the curve between -VA and –IA.

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Thevenin’s Theorem


Thevenin’s Theorem



Theorem:- In a linear lumped bi-lateral network, the current  flowing through any branch or load resistor(R1) can be obtained by reading the circuit into a voltage source(VTM) and a series connected resistor(RTH).
             IL= VTH/RTH+RL
2) The circuit connection are given as shown in the circuit diagram.

3) The Switches circuit  SW1, SW2, and SW3 are closed and the current flowing through load resistor(RL) is noted .

4) The load resistor removed by opening switch SW3. The open circuit  voltage is measured across terminal AB.

5) Short circuit the terminal AB and short circuit current ISC is noted. The value of RTHis given by RTH= VOC/ISC

6) The current flowing through the load resistor RL is calculated by using the thevenin’s formula.
                              IL=VTH/RTH+RL

7) By verifying the value of resistance by R1,R2 and R3 different set of reading  obtained and are tabulated.


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Thursday, 14 April 2016

Maximum Power Transfer Theorem

1) In a linear bi-lateral network maximum power transfer theorem states that the maximum power will be transferred from source to load. When load resistance is equal to internal resistance in a D.C circuit.
2) The circuit connection are made as shown in the circuit diagram.
3) The value of Rh1 the voltage across the current following through the load resistance to Rh2 is measured.
4) The value of Rh2 is varied and the reading of ammeter and voltmeter are noted.
5) Now change the value of Rh1 and for various of Rh2 the ammeter and voltmeter reading are noted.
6) For every value of Rh1 the power consumed by load resistance is calculated.
7) A plot is made between power consumed and value of load resistor .



Equipment used
 Power Supply (12V / 9V) D.C  × 1 No.
D.C Voltmeter (0 - 15V)             × 1No.
D.C Ammeter (0 - 5 amp)          × 1 No.
Variable resistor (0 - 1k)           × 1 No.


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Thursday, 31 March 2016

Layout Circuit Of 100 Watt Square Wave U.P.S




Components Required
1- Transformer 12 - 0 - 12
2- IC4013
    IC NE555
3- Transistor 2N3055 × 2
4- Capacitor 200mf
                       2mf / 400V
                       10kpf × 2
                       220kpf
                       100mf / 25V
5- Diode.       IN4002 × 2
                       IN5406 × 2

About this circuit >>

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Tuesday, 22 March 2016

Solar Photovoltaic Cell (PV)

A solar cell , or photovoltaic cell (PV), is a device that converts light into electric current using the photovoltaic effect . The first solar cell was constructed by Charles Fritts in the 1880 . The German industrialist Ernst Werner von Siemens was among those who recognized the importance of this discovery. In 1931, the German engineer Bruno Lange developed a photo cell using silver selenide in place of copper oxide , although the prototype selenium cells converted less than 1% of incident light into electricity. Following the work of Russell Ohl in the 1940s, researchers Gerald Pearson, Calvin Fuller and Daryl Chapin created the silicon solar cell in 1954.These early solar cells cost 286 USD/ watt and reached efficiencies of 4.5–6%.

Solar Energy

Solar power is the conversion of sunlight into electricity, either directly using photovoltaic (PV), or indirectly using concentrated solar
power (CSP). Concentrated solar power systems use lenses or mirrors and tracking systems to focus a large area of sunlight into a small beam. Photovoltaic convert light into an electric current using the photovoltaic effect .
The International Energy Agency projected in 2014 that under its "high renewables" scenario, by 2050, solar photovoltaic and concentrated solar power would contribute about 16 and 11 percent, respectively, of the worldwide
electricity consumption , and solar would be the world's largest source of electricity. Most solar installations would be in China and India. Photovoltaic were initially solely used as a source of electricity for small and medium- sized applications, from the calculator powered by a single solar cell to remote homes powered by an off-grid rooftop PV system. As the cost
of solar electricity has fallen, the number of grid-connected solar PV systems has grown into the millions and utility-scale solar power stations with hundreds of megawatts are being built. Solar PV is rapidly becoming an inexpensive, low-carbon technology to harness
renewable energy from the Sun.
Commercial concentrated solar power plants were first developed in the 1980s. The 392 MW Ivanpah installation is the largest
concentrating solar power plant in the world, located in the Mojave Desert of California . The 579 MW Solar Star , near Rosamond, California , is the world's largest PV power station .

Monday, 21 March 2016

MOSFETs

Power MOSFETs
A metal oxide semiconductor Field Effect Transistor (MOSFET) is combination of field effect concept and MOS technology.
The MOSFET is three terminal (gate, drain, source) four layer semiconductor device. MOSFET is a majority carrier device and as the majority carrier have no recombination delays, the MOSFET achieves extremely high bandwidths and switching times.
Working of Power MOSFETs
When gate is positive with respect to source an accumulation layer is formed in the layer channel as figure below. This accumulation layer is formed because of Vgs . The gate terminal(metal) is positive. The other side of oxide layer is p-type of body region.

Application of Power MOSFETs
(1) They are used in input amplifiers in oscilloscope and electronic voltmeters.
(2) They are used in logic circuits, for mixer operation of FM and TV receiver.
(3) They are used as voltage variable - resistors in computer memories.

Saturday, 19 March 2016

Transformerless A.C 220V , 50Hz to 6.2V D.C

Transformerless 220V , 50Hz to 6.2V D.C
Components Required
1- Capacitor 2.2uf/400V × 1,
                      1000uf/25V × 1,
2- Resistance 1k × 1,
3- Diodes IN4007 × 4,
4- Zener Diode 6.2V × 1,

Circuit Diagram

220 AC 50 Hz to 9 V DC

220 AC 50 Hz to 9 V DC
Components Required
1- 12-0-12 Step down Transformer
2- Diode IN4007 × 4
3- Capacitor 1000uf/16V × 1
4- IC7809 × 1

Simple Mobile Power Bank Circuit Diagram

Make homemade mobile power bank
Components Required
1- 9 V Rechargeable Battery
2- Voltage Regulator IC7805
3- Resistance 1K ohm
4- LED 3mm
5- USB Port